pH=−log[H+]=−log(6.32×10-3)≈2.20pH equals negative log open bracket cap H raised to the positive power close bracket equals negative log open paren 6.32 cross 10 to the negative 3 power close paren is approximately equal to 2.20 Part B: pH at the Equivalence Point At the equivalence point, all HNO2cap H cap N cap O sub 2 reacts with NaOHcap N a cap O cap H to form the conjugate base, NO2−cap N cap O sub 2 raised to the negative power
The 1972 exam expected students to explicitly state that at a constant temperature, all gases have the same average kinetic energy, but different velocities. 3. Thermodynamics: Entropy and Enthalpy 1972 ap chemistry free response answers
1.6×10-5=s′(0.10)21.6 cross 10 to the negative 5 power equals s prime open paren 0.10 close paren squared pH=−log[H+]=−log(6
PN2O4=1.00 atmcap P sub cap N sub 2 cap O sub 4 end-sub equals 1.00 atm : 1972 ap chemistry free response answers
: Exams from the 1970s did not rely on graphing calculators; numbers are often structured to simplify easily via mental math or basic algebra.